chunk_30.json•1.5 kB
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"text": "500 H4 = H3 + TS 30. 092 Feet \n510 P2H = 0.50*W1/1000*H4^2*COS(K3)*K4 15.075 \n515 P2V = 0.5*W1/1000*H4^2*KA*SIN(K3) 2.661589 \n520 MAH = P2H*H4//3 151.212 \n530 FM = MT/MAH 2.265 \n540 IF FM<1.5 THEN 560 \n550 IF FM>=1.5 THEN 580 \n560 PRINT” Assumed dimension of slab not \nokay failure will be initiated by \noverturning of structure either revise \ndimension L1, L2 or thickness of slab or \nmaterial strength specifications” \n \n570 STOP \n580 REM Determine sliding stability of wall \n585 PRINT” Overturning stability of wall okay” \n590 KB = COS(K3)*(COS(K3) + K1)/(COS(K3)-\nK1) \n3.2946 \n600 KP1 = KB^.5 1.8151076 \n610 REM Take C as 0.625 Average value \n615 K5 = 0.0174533*B3 .5585150 \n\n262 \n \n620 FR = WT*TAN(K5) + 0.625*C*L4 28.8588 \n630 REM Let PP passive force supporting slab \n640 PP = 0.5*W2*KB*(H1-TS)^2/1000 + \n2*C*(H1-TS)*KP1 \n4.981696 \n650 SFH = PP + FR 33.85692 \n660 REM P2H = Force causing horizontal \nmotion \n \n670 REM Let FU actual factor of safety for \nsliding must not exceed 1.5 as per code \nrequirement.",
"metadata": {
"book_id": 34880,
"title": "BASIC-STRUCTURAL-388457483-Retaining-Wall-Design-Analytical-and-Computer-Methods-By-Ben-David-CE",
"authors": "Ben David",
"project": "basic_structural",
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