chunk_15.json•1.51 kB
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"text": "ah’\n = 1/2(y)(H’)\n2\n(K\na\n) = 0.50(30.1)\n2\n(0.115)(0.294) – 15.1 \nFrom these data’s and wall dimensions we can set up the following in table form \nPART Weight, Kips Arm, Foot Mr’ ft - \nkips \n1 0.5(26+27.65) x 0.115(9.5) = 29.3 9.67 283.3 \n2 1.33 x 26 x 0.15 x 1 =5.2 4.28 22.1 \n3 0.5 x 0.59 x 26 x 0.15 = 1.2 3.39 4.0 \n4 2.42 x 14.42 x 0.15 x 1 = 5.2 7.21 37.5 \nP\nav’\n = P\nah’\n(sin10 ) = 15.1 sin 10 = 2.6 Kips \n/Foot \n14.42 37.5 \n\n251 \n \nTotal Sum Sum weight = 43.15 \n \nSum \nOverturning \nM = \n 384.4 Foot \nKips \n \nTaking moments at toe the overturning moment is MO \nmo = P’\nAH\n \n \n = \n151 Ft Kips/foot here \n \n = 1/3 x h = \n \n \n = 151 Ft kips/foot \nThe safety factor is sum \n \n \n = \n \n \n = 2.54 greater than 1.5 Okay. Here 1.5 is the \nrecommended factor of safety against overturning which is equals to 1.5 \nDetermine sliding stability of wall. The factor of safety against sliding will be based on using \n3 feet of depth of soil at the toe. \n \nK\np\n = tan\n2\n(45 +",
"metadata": {
"book_id": 34880,
"title": "BASIC-STRUCTURAL-388457483-Retaining-Wall-Design-Analytical-and-Computer-Methods-By-Ben-David-CE",
"authors": "Ben David",
"project": "basic_structural",
"content_source": "ocr",
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