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Calibre RAG MCP Server

by ispyridis
chunk_351.json1.4 kB
{ "id": "chunk_351", "text": "3: Ordonnee. \nI , \nX< I >, V < 1 >=? 1 0 0 \nI' X< I >, V< 1 >=? 2 0 5 \nI, X< I>, V<l >=? 3 a 5 \nI, X< I>, V<l>=? 4 a 0 \nVal idez-Vous les Donnees: Oui=1 ' Non=O? 1 \nL1·1~nNe: Descr ipti~n des Points Parametres· \n. umero du Po\n1\nnt · 2 Lignes de 5 valeurs \n2: Abscisse <=O po~r Parametre Px non nul) \n3 : Ordonnee <=O pour Parametre ' \n4 N Py non nu 1 ) \n.\n: \numero du Parametre Px pour Ab ' \n5 Nu d scisse <Abscisse=O> \n. mero u Parametre Py pour Ordonnee < Ordonnee=O). \n3eme \nI, X< I>, V<l >, Px, Py=? 50 5 1 \nI, X< I>, V<l >, Px, Py•? 6 0 0 2 3 \nValidez-Vous les Donnees: Oui-1 \nNon=O? 1 \n526 \n-\n4DRLLRUPT \n4eme Ligne: Description des Points lntersections• de Droites: 3 Lignes de 5 val \n1: Numero du Point, \n2 et 3: Numeros des Deux Points definissbnt Ia 1ere Droite, \n4 et 5: Numeros des Deux Points definissant Ia 2eme Droite. \n1, 11, 12, 13, 14=? 7 3 4 5 6 \nI I \n1, 12, 13, 14=? a 4 5 1 2 \nI ' I 1 , 12, 13, 14=? g a 6 1 4 \nV~l idez-Vous les Donnees: Oui=1 , Non=O? 1", "metadata": { "book_id": 34848, "title": "BASIC-STRUCTURAL-Henry-Thonier-Tome-2", "authors": "Unknown", "project": "basic_structural", "content_source": "ocr", "content_length": 756676, "chunk_index": 351, "line_start": 12420, "line_end": 12455, "has_formulas": false, "has_tables": false } }

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