Calibre RAG MCP Server

{ "id": "chunk_21", "text": "***Note author by computer use the mathematical expression below *** See \nchapter 4 \n \n*** Note given d, b and Mu depth of stress rectangular block is \n a = d ± d\n2\n \n– \n \n For Computer application \n \nAs = Mu/( f\ny\n(d – a/2)) to solve areas of steel reinforcements as sub routines \nprogram within the main program both heel and stem portions (See program listings) \n \n \n \n Below is the load, shear and moment diagram \n\n255 \n \n 3 Ft 9.5 Ft \n q = 2.429.15) = 0.36 STEM Q = 2.42(1.5)+26.8(.115) = 3.45 KSF \n \n pressure diagram heel and toe o.7 k.s.f. \n 5.3 k.s.f. 1 .32 \n \n \n TOP OF WALL TOP OF WALL TOP OF WALL 16” \n Z 1.4 Ft kips .2h 17.4” \n 22 Ft kips .5h 19.5” \n .8h h 21.6” \n 90 Ft kips h 23”", "metadata": { "book_id": 34880, "title": "BASIC-STRUCTURAL-388457483-Retaining-Wall-Design-Analytical-and-Computer-Methods-By-Ben-David-CE", "authors": "Ben David", "project": "basic_structural", "content_source": "ocr", "content_length": 39295, "chunk_index": 21, "line_start": 946, "line_end": 980, "has_formulas": false, "has_tables": false } }