chunk_765.json•1.56 kB
{
"id": "chunk_765",
"text": "Mhypmax = -6 f.! PI (5 L\n2\n) \n=-6 (-14,211) X 1080 I (5 X 14,5\n2\n) = 87,60 kNm \nNo \nLongueur Hauteur Type A ire \nDistance de Moment \nson cdg statique \nfigure \n52 b h k \nS=kbh aAou C: d \nf!•Sd \n1 \nL/3 \ne1 \nTriangle 0,5bh A: 2 L/ 9 \n4,8333 \n-0,2300 \n0,5000 \n-0,5558 3,2222 \n-1,7910 \n2 \nL/3 \ne1 \nRectangle bh \nA: L/2 \n4,8333 \n-0,2300 1,0000 -1,1117 \n7,2500 -8,0596 \n3 L e\n1\n/3/(e\n1\n-ea) \ne1 \nTriangle \n0,5bh A: 2L/3 +b/3 \n2,4167 -0,2300 0,5000 -0,2779 \n10,4722 \n-2,9104 \n4 \nLe\n8\n/3/(e\n8\n-e1) \nea \nTriangle 0,5bh A:L-b/3 \n2.4167 \n0,2300 0,5000 \n0,2779 \n13,6944 \n3,8059 \n5 \nL \ne\n8\n/3/(e\n8\n-e\n2\n) \nea \nTriangle \nbh C: L/2 \n2,6468 0,2300 0,5000 \n0,6088 \n7,2500 \n4,4136 \n6 \nL \ne\n2\n/3/(e\n2\n-ea) \ne2 \nTriangle bh \nc: L/2 \n2,1865 \n-0,1900 \n0,5000 \n-0,4154 \n7,2500 \n-3,0119 \n7 \nL/3 \ne2 \nRectangle 2bh C: L/2 \n2,4167 -0,1900 1,0000 -0,9183 \n7,2500 \n-6,6579 \nMoment statique total \n-14,2113 \nMoment hyperstatique kNm \n87,600 \n725 \n\n• Moments dus aux charges permanentes g\n1 \net g\n2 \nPour Ie calcul des moments, on pourra utiliser les formules des cas 70, 71 et 72 du formu-\nlaire du chapitre 2",
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"title": "BASIC-STRUCTURAL-Henry-Thonier-Tome-2",
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