chunk_543.json•1.51 kB
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"text": "Cas 5 : Reaction d'etai R = 1,25 g\n1 \nL\n0 \n= 1,25 x 1,73 x 2,87 = 6,21 kN \n1,91 \n140 \n240 \n100 \n-5,47 \nMR \n1/v \n626 \nCas 6: q\n1 \n= 0,93 kN/m Mqlmax = 3 ql L\n2\n/32 = 2,873 kNm \net Mqlmin =-q\n1 \nL\n2\n/32 =-0,958 kNm ' \n140 \n240 \n100 \n0,98 \n-0,60 \n-2,82 \nMqlmax \n1/v \nou \n-0,33 \n0,\n20 \n0 ,94 \nMqlmin \nltv \nCas 7: LlP = P\n1\n-\nP = 0,00464 MN, excentricite e =-0,1413 m \nCombinaison 1 = cas 1 \nOn verifie bien que : \n240 \n140 \n100 \nO'comp = 13,29 < 2fcjof3 = 20 MPa OK \net O'tract = -0,89 > -4 MPa OK \nCombinaison 2 =cas (1 + 2 + 3) \n-0,12 \n-0,12 \n0,22 0,10 \n+ \n-0,26 \n-0,64 \n-0,36 \n... I ~ .. J ·\\ 4~ \n9,85 -0,73 \n5,37 14,49 \nOn verifie bien que : \ncr = 14 49 < 2 f ·\n1\n/3 = 26,67 MPa OK \ncomp • CJ \net O'tract = -3,30 > -4 MPa OK \nCombinaison 3 = combinaison 2 car Mqomax = 0 \n627 \n\nCombinaison 4 = cas (1 + 2 + 3 + 4 min) \n14,49 \nOn verifie bien que : \ncrcomp = 16,04 < 2fcjt /3 = 26,67 MPa OK \nCombinaison 5 = cas (1 + 2 + 3 + 5) \n·3,30 \n140 \n'h \n14,49 \nOn verifie bien que : \ncrcomp = 9,02 < 0,5fc\n28 \n= 12,5 MPa OK \net crbas = 9,02 > -1 MPa OK",
"metadata": {
"book_id": 34848,
"title": "BASIC-STRUCTURAL-Henry-Thonier-Tome-2",
"authors": "Unknown",
"project": "basic_structural",
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