chunk_413.json•1.57 kB
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"text": "0,0000 \n(m) \n(0,00) \nx2 \n0,8203 \n(m) \n(4,43) \nCas3 \n-\np (kN/m\n2\n) \n10,28 \nM (kNm/m) \n0,00 \nXo \n0,3889 \nMmax (kNm/m} \n22,67 \nx1 \n0,0000 \n(m) \n• (0,00) \nx2 \n0,7779 \n(m) \n(4,20) \nX1max \n(m) \n0,34 \nl-X2max \n(m) \n1,20 \nLargeurs des bandes et repartition des moments (d'apres Fig.68) \nLes largeurs des bandes valent (Fig.74): \nAppui 2 Travee 2 \n14,04 \n-40,46 \n0,5000 \n10,72 \n0,2712 \n(1,46) \n0,7288 \n(3,94) \n10,28 \n-36,79 \n0,5000 \n0,68 \n0.4326 \n(2,34) \n0,5674 \n(3,06) \n14,04 \n-33,29 \n0,5000 \n17,88 \n0,2044 \n(1,1 0) \n0,7956 \n(4,30) \n2,34 \n2,34 \n557 \n\nL>a: 1:5 ~,5 'b + h~ = 1,5 (0,6/2 + 0,25) = 0,825 m < 0,25 Ly = 1,25 m OK \nL yr L la Lx / 10 -0,825 + 0,54 = 1,365 m > 0,25 L = 1,25 m, done L' = 1 25m \nles travees 1 et 3 et L'yr = 1,365 m < 5,5/4 = 1,375 mypour Ia travee 2. yr , pour \nbar1d• d • .,..;.,. i. \nbo\"<lt Ctnt»o k i \n0 \n\"' \n1\\' \n.band• <l'opf'<'i 1 \nb....,dt Ct .. t.-.1< l_ \n~ \nI \nII\\ \nI ~•nd# d 'o,.,>ui C. \nl>anclt ~nl:.oo k 3 ~ \nI \n\"' \n................. \nl \n,lT\"\"v\"'.!• .'.40 ~ r-w• 3. HO \n'--3,,~3 I.H,,t... '17,N~N ... /m \n.40,24 \" • \n-44UioN\"'\"\" _.u,oB~H...A.,",
"metadata": {
"book_id": 34848,
"title": "BASIC-STRUCTURAL-Henry-Thonier-Tome-2",
"authors": "Unknown",
"project": "basic_structural",
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